10=-16t^2+60t

Solution for 10=-16t^2+60t equation:

10=-16t^2+60t

We move all terms to the left:

10-(-16t^2+60t)=0

We get rid of parentheses

16t^2-60t+10=0

a = 16; b = -60; c = +10;
Δ = b2-4ac
Δ = -602-4·16·10
Δ = 2960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2960}=\sqrt{16*185}=\sqrt{16}*\sqrt{185}=4\sqrt{185}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{185}}{2*16}=\frac{60-4\sqrt{185}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{185}}{2*16}=\frac{60+4\sqrt{185}}{32}
$